Failure inserting into the read only column "TimeValue"
I have a SQL destination table with foll columns.
CREATE
TABLE [dbo].[Staging_JCDS_PM_CM_Initial](
[Name] [nvarchar](255)
NULL,
[DateValue] [datetime] NULL,
[TimeValue] [timestamp] NULL
)
ON [PRIMARY]
I have ths table as SSIS - OLEDB destination. Source is from a CSV file.
I get an error on TimeValue column saying
"Failure inserting into the read only column "TimeValue"
Please help to solve this ....
Thanks in Advance.
Added: Temporarily I have changed datatype Timestamp to varchar(50). and i use
convert(varchar,TimeValue,
108)
to convert varchar to Timestamp.
May 9th, 2011 2:34am
1) Is there a default on TimeValue above and it is missed in the script above.
2)If there is a default and trying to insert , this error maight appear.Happy to help! Thanks. Regards and good Wishes, Deepak.
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May 9th, 2011 2:48am
1) Is there a default on TimeValue above and it is missed in the script above.
2)If there is a default and trying to insert , this error maight appear.
Happy to help! Thanks. Regards and good Wishes, Deepak.
Nope. There is no default value.
May 9th, 2011 2:53am
The SQL Server timestamp data type is a binary number maintained by the SQL Server engine. Don't confuse it with the SQL Server
datetime or the SQL-92 standard timestamp. Columns with a data type of Timestamp are readonly.Jeff Wharton MSysDev (C.Sturt), MDbDsgnMgt (C.Sturt)
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May 9th, 2011 4:17am
timestamp is a data type that exposes automatically generated binary numbers, which are guaranteed to be unique within a database
http://msdn.microsoft.com/en-us/library/aa260631(SQL.80).aspxHappy to help! Thanks. Regards and good Wishes, Deepak.
May 9th, 2011 4:24am
The SQL Server timestamp data type is a binary number maintained by the SQL Server engine. Don't confuse it with the SQL Server
datetime or the SQL-92 standard timestamp. Columns with a data type of Timestamp are readonly.
Jeff Wharton MSysDev (C.Sturt), MDbDsgnMgt (C.Sturt)
OOps. Thnks for being my eye opener !!!
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May 10th, 2011 1:13am
No problem and thanks for marking your question as answered.Jeff Wharton MSysDev (C.Sturt), MDbDsgnMgt (C.Sturt)
May 10th, 2011 1:17am